G'day fidda,
This does what you want:
#!/usr/bin/env perl
use strict;
use warnings;
use Data::Dump;
my @A = qw{H1 H2 H3 H4};
my @B = 1 .. 10;
my %result;
my $reverse = 0;
while (@B) {
build_hash(\%result, \@A, \@B, $reverse);
$reverse ^= 1;
}
dd \%result;
sub build_hash {
my ($result, $A, $B, $reverse) = @_;
my @keys = @$B >= @$A ? @$A : @$A[0 .. $#$B];
my @values;
if ($reverse) {
unshift @values, shift @$B for (0 .. $#keys);
}
else {
push @values, shift @$B for (0 .. $#keys);
}
push @{$result->{$keys[$_]}}, $values[$_] for 0 .. $#keys;
}
Output:
{ H1 => [1, 8, 9], H2 => [2, 7, 10], H3 => [3, 6], H4 => [4, 5] }
Note that this code destroys @B.
If you need to keep it, make a copy and use that in the while condition and when calling &build_hash:
my @B_copy = @B;
...
while (@B_copy) {
build_hash(\%result, \@A, \@B_copy, $reverse);
...
Furthermore, the subroutine &build_hash has no reliance on the initial values of either @A or @B.
For example, these initial values:
my @A = qw{H1 H2 H3 H4 H5};
my @B = 1 .. 23;
produce this output:
{
H1 => [1, 10, 11, 20, 21],
H2 => [2, 9, 12, 19, 22],
H3 => [3, 8, 13, 18, 23],
H4 => [4, 7, 14, 17],
H5 => [5, 6, 15, 16],
}
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