> Keep in mind that perl currently doesn't do nested subs
Ack, how un-DWIM!
sub foo {
my $x = "a var in foo()";
sub bar {
print "\$x is - [$x]\n";
}
}
bar();
__output__
$x is - []
But if we use a closure, all is well with the scope of $x
sub foo {
my $x = "a var in foo()";
return sub {
print "\$x is - [$x]\n";
}
}
foo()->();
__output__
$x is - [a var in foo()]
I was vaguely aware of the fact that nested subs in perl were broken (i.e scoped to current package, not current sub) and now I know the full extent (but I guess the logic should've followed really). Oh well, not much longer til Perl6 anyway ...
HTH
broquaint
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