You want to sort the whole row as a string, then sort on the first column numerically, correct?
#!/usr/bin/perl -w
use strict;
my @sorted = map {$_->[0]} sort {
$a->[0] cmp $b->[0] ||
$b->[1] <=> $a->[1]
} map {[ $_ ,/(\w+)\s+(\w+)\s+(\w+)/]} <DATA> ;
print for @sorted;
__END__
2 4 a
1 9 b
6 8 a
UPDATED
My mistake- I thought you were asking a perl perlfunc:sort question, rather than Gnu sort. (I also didn't realize that this was a mid-thread revision of the subj. line .). For a perl question, then you would be looking for...
my @sorted = map {$_->[0]} sort {
$a->[3] cmp $b->[3] || # sorted ascending alpha on col 3
$b->[2] <=> $a->[2] # then sorted reverse num on col 2
} map {[ $_ ,/(\w+)\s+(\w+)\s+(\w+)/]} <DATA> ;
print for @sorted;
(I think..)
UPDATED2
Gnu sort's index starts with 0. The last column would be "2" not "3". Does this help, rchou2?
mkmcconn
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