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Think about Loose Coupling

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I still think its the former.
Given that
%data = << why dunno who them where there which this >>;
I would assume that writing *%data in any context is equivalent to writing
(why => "dunno", who => "them", where => "there", which => "this")
So assuming we can use this as an lvalue, an assignment with a list of pairs to this would be the same as taking each pair and assigning it to the value with the specific key. So *%data = *%values should be compiled as
multi sub infix:=(List of Pair @assign is rw, List of Pair @values) re +turns List of Pair { my %assign := *@assign; for @values { %assign{.key} = .value; } return *%assign; }
Let me take another example and go back to part(). We could write:
my $fish = "hest"; ($sheep, $goats, $fish) := part Animal::Cat, @animals;
So the question here is, is $fish eq "hest" after this, or undef?
Alternatly we could have written
my $hest = "hest"; %result := ($sheep, $goats, fish => $hest) := part Animal::Cat, @anima +ls;
Would that give the same result?

Update: Forgot the multi keyword
Update: As broquaint pointed out below, I forgot to use the binding operator as I indented to...
Update: And the second example is completly bogus, because it would endeed result in a compile time error. Was
($sheep, $goats, $fish => "hest") := part Animal::Cat, @animals;


In reply to Re: Re: Re: Re: Exegesis 6 - Named binding by Cine
in thread Exegesis 6 - Named binding by Cine

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