I've enjoyed assisting, where I can, others with very similar queries to the one I'm asking here, but I'm having a mental block and can't seem to think of a way to do the following.

I have a hash:

%properties = ( if_mac => { 0 => { value => '00:11:1A:F2:E1:92',
                                   fixed => 0
                                   },
                            1 => { value => '00:11:1A:F2:E1:93',
                                   fixed => 0
                                   },
                            },
                if_ip => { 0 => { value => '132.181.30.3',
                                  fixed => 0
                                  },
                           1 => { value => '132.181.30.4',
                                  fixed => 0
                                  },
                           }
                );
[download]

I want to convert it into a flat array of just the properties:

my @values = ( [ 'if_mac', 0, '00:11:1A:F2:E1:92' ],
               [ 'if_mac', 1, '00:11:1A:F2:E1:93' ],
               [ 'if_ip', 0, '132.181.30.3' ],
               [ 'if_ip', 1, '132.181.30.4' ]
               );
[download]

I could loop over the hash and build up the array, but I would like to be more clever and use the map { } function. The problem is that I am trying to build an array of arrays with three columns in it. I solved a similar problem in another perlmonk question (Re: Hash of array of hashes in reply to Hash of array of hashes) by creating an anonymous array reference in a sub-map function call.. I wonder if something similar could be done here?

Any ideas?

Update: changed curly braces to parenthesis on suggestion by davidrw. Problem solved neatly by Transient.