which to me looks like:
$OPER = 's' = 'c';
when $test ne 'c' is true. And that should fail with a "Can't modify constant item in scalar assignment" error. However no errors and no warnings are generated for either condition.
Using ?: to select a variable to be assigned to I'm happy with:
test ? $p1 : $p2 = value;
but the half assignement variant implied by the precedence (and made explicit by the brackets shown in your reply) is just bizare.
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