bikeNomad's solution 1 does not take into account
the probability that the values may be the same,
but that they are not tied to the same key. So:
my @k1 = keys(%hash1);
my @k2 = keys(%hash2);
# do they have the same number of elements?
if (@k1 != @k2) { # they're different...
}
# are the keys the same?
if ((join $; , sort @k1 )
ne join $; , sort @k2)) { #they're different
}
# are the values the same?
if ( scalar grep { $hash1{$_} ne $hash2{$_} } @k1 )
{ #they're different
}
Number warning still applies.
Jeroen
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