Re^2: Using overload to parse arithmetic terms

in reply to Re: Using overload to parse arithmetic terms
in thread Using overload to parse arithmetic terms

well i, did that:

use overload
    '+' => \&add,
    '-' => \&sub,
    '*' => \&mul;
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so, i'm able to build a expression that uses +, - and * . Now, i want to be able to detect when the user uses parenthesis as shown above. I know that overload does not support parenthesis, but i hope that somebody has a idea how i can detect those parenthesis.

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Re^3: Using overload to parse arithmetic terms by Tomte (Priest) on Feb 07, 2006 at 12:57 UTC
Hmm, how do you store the expressions? If you store them as a tree, you already have the information necessary, because you can always generate parenthesis for an <+\|->-Node with to children on the fly - that's what I meant with showing relevant code - do you store the expression as a tree - otherwise this is a useless info on my part g? regards, tomte An intellectual is someone whose mind watches itself. -- Albert Camus	[reply] [d/l]

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Re^3: Using overload to parse arithmetic terms
by Tomte (Priest) on Feb 07, 2006 at 12:57 UTC

Hmm, how do you store the expressions? If you store them as a tree, you already have the information necessary, because you can always generate parenthesis for an <+|->-Node with to children on the fly - that's what I meant with showing relevant code - do you store the expression as a tree - otherwise this is a useless info on my part *g*?

regards,
tomte

An intellectual is someone whose mind watches itself.
-- Albert Camus

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