Re: Changing local variables in subroutine by passing by reference?

in reply to Changing local variables in subroutine by passing by reference?

You have a precedence problem in your dereferencing ($$_[2] and @$_[1]), i.e. you need additional braces. And, as moritz said, you need to dereference in the assignment, too. IOW, this should work:

    ...
    print "count is: ${$_[2]} , reference is: $_[2] \n";
    print "data  is: @{$_[1]} , reference is: $_[1] \n";
    ${$_[2]} = 0;
    @{$_[1]} = ();
    ...
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Re^2: Changing local variables in subroutine by passing by reference? by why_bird (Pilgrim) on Feb 29, 2008 at 10:32 UTC
That might answer my question before.. I'll read up on operator precedence.. Thanks :) ------------------------------------------------------------- Those are my principles. If you don't like them, I have others. -- Groucho Marx --------------------------------------------------------------	[reply]

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