Here is a little piece of code you might find informative:

#!/usr/bin/perl

$a = shift;
$b = shift;

#for intergers only
if ($a =~ /^\d+$/ && $b =~ /^\d+$/) {
    printf "$a == $b (%s)\n", $a == $b ? "yes" : "no";
} else {
    printf "$a eq $b (%s)\n", $a eq $b ? "yes" : "no";
} 

#or for floating point numbers
if ($a =~ /^\d+(\.\d?)?$/ && $b =~ /^\d+(\.\d?)$/) {
    printf "$a == $b (%s)\n", $a == $b ? "yes" : "no";
} else {
    printf "$a eq $b (%s)\n", $a eq $b ? "yes" : "no";
}
[download]

> perl diff 1 1.
1 eq 1. (no)
1 == 1. (yes)

This still needs work, as it does not see that 1e2 == 100.



-- gam3

A picture is worth a thousand words, but takes 200K.

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