Here is quick but cheap way to do it. Im just posting the progress routine but in the main routine you also have to toss the percent variable and instead have a variable keep track of total bytes writen. Then call this sub passing it total_writen, and file size. This routine also uses fastolfe's suggestion of using \r instead of \n so just the line is updated ( works on win2k too!).

sub FileProgress () {
    my $wrote       = shift;
    my $size        = shift;
    my $percent     = $wrote / $size * 100;
    
    case: {
            if ($percent <11)     { print "\r[*         ]"; last;}
            if ($percent <21)     { print "\r[**        ]"; last;}
            if ($percent <31)     { print "\r[***       ]"; last;}
            if ($percent <41)     { print "\r[****      ]"; last;}
            if ($percent <51)     { print "\r[*****     ]"; last;}
            if ($percent <61)     { print "\r[******    ]"; last;}
            if ($percent <71)     { print "\r[*******   ]"; last;}
            if ($percent <81)     { print "\r[********  ]"; last;}
            if ($percent <91)     { print "\r[********* ]"; last;}
            if ($percent <=100)   { print "\r[**********]"; last;}
    }
    printf " %3u",$percent;
    print '%';
    printf " done. %u bytes.",$wrote;    
    return 1;
}
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zzSPECTREz

You probably don't want to be using a prototype of () for this sub as you'll be trying to pass arguments to a sub that (regardless of the shifts inside the sub) doesn't take any!

You can also simplify things greatly by performing another sum (to get rid of that case: { ... })in combination with a single printf()...

    sub FileProgress {
        my $wrote       = shift;
        my $size        = shift;
        my $percent     = $wrote / $size * 100;
    
        printf "\r[%-10s] %3u%% done. %u bytes", 
            '*' x int( $percent / 10 ),
            $percent,
            $wrote;

        return 1;
    }
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    --k.

Update: Removed the trailing \n.