http://qs1969.pair.com?node_id=837543


in reply to Empty List miracle(1)

If I understand things correctly:

qw,, in scalar context returns undef, however in list context (assigning to an array), it will set the array to an empty array.

Similarly for ().

The real issue here is the differences between returning data in list and scalar context.

So, if you substitute your print statements for these, you will get '0' printed 3 times.

my @a; print(scalar(@a=empty_list1()),"\n"); print(scalar(@a=empty_list2()),"\n"); print(scalar(@a=empty_list3()),"\n");

Replies are listed 'Best First'.
Re^2: Empty List miracle(1)
by ikegami (Patriarch) on Apr 30, 2010 at 14:50 UTC

    Yes, but not for the reason you're implying. You're thinking @a is evaluated in scalar context when it's not. Both operands of the list assignment (@a and empty_listX()) are evaluated in list context.

    If @a is an operand of the list assignment, what's the operand of the scalar() pseudo-operator? The list assignment. scalar() causes the list assignment to be evaluated in scalar context. In scalar context, the list assignment operator returns the number of elements returned by its right hand side operand.

    Since it doesn't matter to what you are assigning, you could just as easily have written

    print(scalar(()=empty_list1()),"\n"); # 0 print(scalar(()=empty_list2()),"\n"); # 0 print(scalar(()=empty_list3()),"\n"); # 0 print(scalar(()=(4..6) ),"\n"); # 3