Not quite, that second = should be a =~, and the shorter (more idiomatic, I'd say) way to write that is:

(my $output = $string) =~ s/\Q$oldstring\E/$newstring/gs;

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In reply to Re^4: problem with perl 5 by Anonymous Monk
in thread problem with regex in perl script intended for 5.20,but while running on 5.10 by praveenchappa

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