# Basic tests
# All input string pairs have at least one common substring

s=abcde
t=bcd77
e=bcd
c=

m= rt52839 Algorithm::LCSS bug
s=CAGAGTTCTACAGTCCGACGATCACTAA
t=ACCGACGATCACTATCGTACGACTCTTAGCAAGCAGA
e=CCGACGATCACTA
c=

m= rt32036 String::LCSS bug
s=1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 2 18 19 20 21 22 23 7 24
t=1 2 3 4 5 7 8 9 11 12 13 10 14 15 16 17 2 18 19 20 21 22 23 7 24
e= 14 15 16 17 2 18 19 20 21 22 23 7 24
c=

m= rt62175 String::LCSS bug
s=the quick brown fox jumped over the lazy dog
t=I saw a quick brown fox and jumped over the lazy dog
e= jumped over the lazy dog
c=

m= BrowserUk lcssN bug
s=xxxyyxxy
t=yyyxyxx
e=yyx
c=

m= BrowserUk lcssN bug
s=abcdefg
t=abcdefga
e=abcdefg
c=

m= Algorithm::LCSS cpan test.pl
s=abcdefghijklmnopqrstuvwxyz
t=flubberabcdubberdofghijklm
e=fghijklm
c=

# String::LCSS cpan test (t/01strings.t)

s=xyzzx
t=abcxyzefg
e=xyz
c=

s=abcxyzzx
t=abcxyzefg
e=abcxyz
c=

s=i pushed the lazy dog into a creek, the quick brown fox told me to
t=the quick brown fox jumps over the lazy dog
e=the quick brown fox 
c=

m= reverse of above s and t
s=the quick brown fox jumps over the lazy dog
t=i pushed the lazy dog into a creek, the quick brown fox told me to
e=the quick brown fox 
c=

s=i pushed the lazy dog into a creek, the quick brown fox told me to
t=why did the quick brown fox jumps over the lazy dog
e= the quick brown fox 
c=


# String::LCSS_XS cpan test (t/10.lcss.t)

s=xyzzx
t=abcxyzefg
e=xyz
c=

s=abcxyzzx
t=abcxyzefg
e=abcxyz
c=

# LCSS_XS=a, japhy=f, browseruk=b
m= 3 possible lcss depending on order: a b f
s=foobar
t=abcxyzefg
e=a
e=b
e=f
c=

s=ABBAGGG
t=HHHHZZAB
e=AB
c=

m= reverse s and t from above
s=HHHHZZAB
t=ABBAGGG
e=AB
c=

s=zyzxx
t=abczyzefg
e=zyz
c=

m= "bug"/"feature" in String::LCSS
s=b
t=ab
e=b
c=

# end String::LCSS_XS cpan test (t/10.lcss.t)

s=____  ___
t=dhfgdja___ 000ghakj
e=___ 
c=

s=111000111
t=10130000555
e=000
c=

s=+=-_)(*&^%$#@!~`|\]}{["';:?/.><, zxcvbnm
t=     xcv-----
e=xcv
c=

m= s=3space,t=7space,e=3space
s=   
t=       
e=   
c=

s=111
t=111
e=111
c=

s=abc
t=cba000
e=a
e=b
e=c
c=