DB<205> for (254..263) {$x = 1000 * ( $_ + 4/25 ); printf "%.20f\n", $x} 254160.00000000000000000000 255160.00000000000000000000 256160.00000000002910383046 257160.00000000002910383046 258160.00000000002910383046 259160.00000000002910383046 260160.00000000002910383046 261160.00000000002910383046 262160.00000000000000000000 263160.00000000000000000000