#!/usr/bin/perl
open (T, ">out") or die "Can't open out $!\n";
printf(T "hello\n");

##</code><code>##

#!/usr/bin/perl
open (T, ">out") or die "Can't open out $!\n";
printf(
T "hello\n");

##</code><code>##

String found where operator expected at ./t.pl line 4, near "T "hello\n""
        (Do you need to predeclare T?)

##</code><code>##

    (S) The Perl lexer knows whether to expect a term or an operator.  If it
    sees what it knows to be a term when it was expecting to see an
    operator, it gives you this warning.  Usually it indicates that an
    operator or delimiter was omitted, such as a semicolon.

##</code><code>##

#!/home/toma/perl58i/bin/perl
use strict;
use warnings;
use diagnostics;
open (T, ">out") or die "Can't open out $!\n";
printf (
T "hello\n");

##</code><code>##

printf (...) interpreted as function at ./t.pl line 6 (#1)
    (W syntax) You've run afoul of the rule that says that any list operator
    followed by parentheses turns into a function, with all the list
    operators arguments found inside the parentheses.  See
    perlop/Terms and List Operators (Leftward).

##</code><code>##

#!/usr/bin/perl
open (T, ">out") or die "Can't open out $!\n";
printf
T "hello\n";