print (1,2)[0];

##</code><code>##

(print(1,2))[0];

##</code><code>##

print((1,2))[0];

##</code><code>##

$ perl -we'print (1,2)[0];' 2>&1 |splain
print (...) interpreted as function at -e line 1 (#1)
    (W syntax) You've run afoul of the rule that says that any list operator
    followed by parentheses turns into a function, with all the list
    operators arguments found inside the parentheses.  See 
    perlop/Terms and List Operators (Leftward).
...