print "row->[0], row->[1]\n";

##</code><code>##

echo Not a SCALAR reference at -e line 108 |splain
Not a SCALAR reference at -e line 108  (#1)
    (F) Perl was trying to evaluate a reference to a scalar value, but found
    a reference to something else instead.  You can use the ref() function
    to find out what kind of ref it really was.  See perlref.