for /l %i in (1,1,1) do @start /b rscript -e "system.time(for(i in
1:1e4){fisher.test(matrix(c(200,300,400,500),nrow=2))})"
user system elapsed
54.50 0.04 54.63
for /l %i in (1,1,2) do @start /b rscript -e "system.time(for(i in
1:1e4){fisher.test(matrix(c(200,300,400,500),nrow=2))})"
user system elapsed
55.64 0.00 55.77
user system elapsed
55.92 0.02 56.08
Test of multiple concurrent R processes on Windows XP on a dual-core machine(R version 2.9.2)
####
$ for i in $(seq 1 1); do Rscript -e 'system.time(for(i in 1:1e4){fisher.test(matrix(c(200,300,400,500),nrow=2))})' & done
user system elapsed
46.694 0.088 47.189
$ for i in $(seq 1 2); do Rscript -e 'system.time(for(i in 1:1e4){fisher.test(matrix(c(200,300,400,500),nrow=2))})' & done
user system elapsed
48.007 0.060 48.188
user system elapsed
47.838 0.072 49.487
####
$ tail Rtest1.txt
0.05
0.05
0.05
0.05
0.05
0.05
0.13
0.08
0.10
0.15
$ wc -l Rtest1.txt
91135 Rtest1.txt
$ cp Rtest1.txt Rtest2.txt
$ cat Rtest1.R
library(splines)
library(survival)
library(NADA)
outcome=scan("Rtest1.txt")
cenoutcome=rep(FALSE, length(outcome))
cenoutcome[outcome==min(outcome)]=TRUE
pyros=cenros(outcome,cenoutcome)
mean(pyros)
proc.time()
# Rtest2.R is the same, but it reads Rtest2.txt
$ Rscript Rtest1.R 2> /dev/null &
[1] 0.03195313
user system elapsed
22.201 4.096 26.293
$ Rscript Rtest1.R 2> /dev/null & Rscript Rtest2.R 2> dev/null &
[1] 0.03195313
user system elapsed
40.358 6.328 46.839
[1] 0.03195313
user system elapsed
39.706 6.044 48.128