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out = new RingBufferEnum(in.get(), 2 * PI * (9*5));

//This somewhat empirical value of 4, in combination with a kMinSample
+sToProcess
//= 16, gives the best performance in the sense of minimizing the like
+lihood of
...
...

out = new RingBufferEnum::Enum( in.get(), (9*5) + 5, 9 * 5 * kMultirat
+eInitNumInnerSamples);