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NOTE: In C++ there are cases where the calling code can "reach into" 
           the function via the returned pointer or reference. 
...
I have been unable to hack into a subroutine via its scalar return. 
If you know of a way it can be done, please let me know, as this would
+ be a horrid violation of encapsulation.

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```
$$ref = "Gore";
```
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```
$ref = \&getGlobalName();
```

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$GlobalName = "Clinton";

...
>>Gore
After: Clinton

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$GlobalName = "Clinton";

...
#prints
Before: Clinton
After: Gore

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$GlobalName = "Clinton";

...
# Also prints
Before: Clinton
After: Gore

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$GlobalName = "Clinton";

...
# Also prints
Before: Clinton
After: Gore