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print (1,2)[0];

(print(1,2))[0];

print((1,2))[0];

$ perl -we'print (1,2)[0];' 2>&1 |splain
print (...) interpreted as function at -e line 1 (#1)
...
    operators arguments found inside the parentheses.  See 
    perlop/Terms and List Operators (Leftward).
...