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printf "%.16e\n", $x;

1.0000000000000000e+000
1.1000000000000001e+000
...
1.9000000000000008e+000
Stop: x=2.0000000000000009e+000
No, x is not 2.

for ( 1*10 .. 2*10 ) {
  my $x = $_/10;
  printf "%.16e\n", $x;
}

1.0000000000000000e+000
1.1000000000000001e+000
...
1.8000000000000000e+000
1.8999999999999999e+000
2.0000000000000000e+000