I'm confused. if BLOCK already creates a scope (in 5.8, at least)

>perl -c -Mstrict -we"if (my $r = f()) { g() }  print($r);"
Global symbol "$r" requires explicit package name at -e line 1.
-e had compilation errors.
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Note that the scope is around the entire statement, so any elsif clauses, "then" blocks, elsif blocks and else blocks will have access to the variable.

>perl -c -Mstrict -we"if (my $r = f1()) { g1() } elsif (my $r = f2()) 
+{ g2() }"
"my" variable $result masks earlier declaration in same scope at -e li
+ne 1.
-e syntax OK
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Update: Nevermind, I understand the question now. Like someone's already said, there's nothing stopping you from creating an explicit block.

>perl -c -Mstrict -we"{ my $r = f(); if ($r) { g() } }  print($r);"
Global symbol "$r" requires explicit package name at -e line 1.
-e had compilation errors.
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Caveat: last, next and redo will ignore the implicit block but will treat the explicit bare block as a loop.

>perl -le"sub f { 1 }  for (1..2) { if (my $r = f()) { next }  print '
+!' }"

>perl -le"sub f { 1 }  for (1..2) { { my $r = f(); if ($r) { next } } 
+ print '!' }"
!
!
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