in reply to Why "getlogin" not works in this case?
The getlogin() syscall returns the user associated with the controlling terminal for the process, or null if there is no controlling terminal.
The way you are running perl, via sh -c, with an & to background it, results in the process having no controlling terminal.
You can more simply see this behaviour with the "tty" command, which shows the controlling terminal.
Normally tty returns something like:
/dev/pts/0
But if you run
sh -c "tty &"
You'll see a different output:
not a tty
If you really want to do what you're doing, consider replacing "getlogin()" with "getpwuid($<)" which uses the real user ID rather than the controlling terminal owner, and so works even backgrounded.
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Re^2: Why "getlogin" not works in this case?
by bdimych (Monk) on Jan 22, 2008 at 16:38 UTC | |
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Re^2: Why "getlogin" not works in this case?
by Anonymous Monk on Mar 26, 2019 at 05:29 UTC |