in reply to Re: How to call a sub-routine ref
in thread How to call a sub-routine ref
And if you don't have an argument to pass, isn't it weird to have empty parenthesis?
$hashref->{'key'}->();
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Re^3: How to call a sub-routine ref
by ikegami (Patriarch) on Oct 19, 2012 at 21:55 UTC | |
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Re^3: How to call a sub-routine ref
by roboticus (Chancellor) on Oct 19, 2012 at 20:36 UTC |