in reply to (tye)Re: Upgrading to new perl environment
in thread Upgrading to new perl environment

Tye; Thanks for your reply, however, I think that the intended application here is:
List context... e.g my documentation says: 
 In list context, it returns a list of the substrings matched by 
any capturing parentheses in the regular expression.  If there are 
no parentheses, it returns a list of all the matched 
strings, as if there were parentheses around the whole pattern.

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This particular line of code  if ($sb =~ /<$fi>\s*(.*?)\s*<\/$fi>/is) { is attempting to capture all the substrings that are taged by string  <$fi>...</$fi>

It is highly possible that I am missing something, but if this is the intended case, do you still think that there is a bug in the application that was tolerated in 5.005 but not in 5.6.0

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(tye)Re2: Upgrading to new perl environment
by tye (Sage) on Jul 26, 2001 at 23:55 UTC

    If the intent was to capture all of the matches, then you'd have to 1) capture them, which would involve, 2) using that construct in a list context.

    As it is used, it is in a scalar (Boolean) context which means that whether there is one match or 20 doesn't make a difference and so the /g modifier doesn't add any value. That is why the /g modifier in a scalar context does something different. It just returns the next match.

    Now if you replace if with while, then the /g would make sense as a way to have the body of the while loop deal with (the text captured by the parens) one match at a time.

    If you have more questions on this, please at least include more code. (:

            - tye (but my friends call me "Tye")
[reply]
      Wow, Tye... thanks. I feel like such a goober. Just goes to show that no matter how much you look at a piece of code you can always miss something. Thanks again; Ed (skeeterpop)
[reply]

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