in reply to parallel functions

Because the first fork creates two processes. One of those processes calls test1, the other does not. Then both processes fork again, creating a total of four processes; two of those processed call test2.

perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'

In Section Seekers of Perl Wisdom