Re^4: Shared hash within shared hash of hash???

I did, it seems to work. I am however, wary of corner cases, when threads are involved.

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Re^5: Shared hash within shared hash of hash??? by zwon (Abbot) on Jan 03, 2013 at 14:44 UTC
I did, it seems to work That's strange, because for me it didn't work: `use threads; use threads::shared; my %sa : shared = (); %{$sa{foo}} = (); __END__ Invalid value for shared scalar at share_share.pl line 5.` [download]	[reply] [d/l]