in reply to Operator precedence

There's no such thing as priority, and neither precedence nor associativity define the order in which stuff is evaluated. They determine what is an operand of what operator. 

apple && (banana || cherry)
   apple:            LHS operand of &&
   banana || cherry: RHS operand of &&
   banana:           LHS operand of ||
   cherry:           LHS operand of ||

(apple && banana) || cherry
   apple && banana:  LHS operand of ||
   apple:            LHS operand of &&
   banana:           RHS operand of &&
   cherry:           RHS operand of ||

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Operand evaluation order is what controls the order in which stuff is evaluated.

In order to provide short-circuiting, && evaluates its LHS operand before its RHS. Same goes for ||.

Given 

apple && (banana || cherry)
   apple:            LHS operand of &&
   banana || cherry: RHS operand of &&
   banana:           LHS operand of ||
   cherry:           LHS operand of ||

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apple must be evaluated before banana || cherry
banana must be evaluated before cherry

So we get:

  1. apple
  2. banana
  3. cherry
  4. ||
  5. &&

Given 

(apple && banana) || cherry
   apple && banana:  LHS operand of ||
   apple:            LHS operand of &&
   banana:           RHS operand of &&
   cherry:           RHS operand of ||

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apple && banana must be evaluated before cherry
apple must be evaluated before banana

So we get:

  1. apple
  2. banana
  3. &&
  4. cherry
  5. ||

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Re^2: Operator precedence
by muba (Priest) on Jan 18, 2013 at 22:43 UTC

    It took me a good couple days to realise what you meant with "There's no such thing as priority, and neither precedence nor associativity define the order in which stuff is evaluated. They determine what is an operand of what operator."

    But I get it now. Looking at it that clarifies a lot. Thank you.

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In Section Seekers of Perl Wisdom