khjayantasingh has asked for the wisdom of the Perl Monks concerning the following question:
################ I give a command line argumentdisplay.pl.... #!/usr/bin/perl print "@ARGV\n";
But It gives an error...perl display.pl net/*/*
If i give argument likeperl: No match.
It is working find... but problem is I cannot use like this in my script.. So please tell me why this script is giving an error... and any means to make it work..perl display.pl 'net/*/*' or perl display.pl "net/*/*"
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Re: Command line argument Error..
by roboticus (Chancellor) on Jan 31, 2013 at 11:14 UTC | |
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Re: Command line argument Error.. (shell)
by Anonymous Monk on Jan 31, 2013 at 11:10 UTC | |
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Re: Command line argument Error..
by vinoth.ree (Monsignor) on Jan 31, 2013 at 11:17 UTC |