Re^3: Replace newlines only if not inside braces

No, there is no difference. I just thought it would be a little bit more efficient. I thought that, if the \K is outside, the $& variable is being cleaned up for every substitution, which is not really necessary. It should be cleaned only when something on the left side has been matched. Anyway, it is more readable in your way, and does, basically, the same thing. :)

Alternatively, to work with strings that contain {{...}} groups, which are not followed by a newline, this code should do it:

$data =~ s<(?:{{.*?}}|[^\n])*\K\n>{<br>\n}gs;
print $data;
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Re^4: Replace newlines only if not inside braces by LanX (Saint) on Feb 11, 2013 at 20:15 UTC
`$data =~ s<(?:{{.?}}\|[^\n])\K\n>{<br>\n}gs;` I think (didn't test it) that the * is two greedy, better *?. Cheers Rolf	[reply] [d/l]
Re^5: Replace newlines only if not inside braces by trizen (Hermit) on Feb 11, 2013 at 21:47 UTC
Nope. It doesn't matter. The group doesn't match a single newline, so it can be greedy. It will try to match either the brackets block or any other character which is not a newline. If it succeeds, then tries again to match the block or a non-newline character. If it fails, it will match the newline character (`\n`) and makes the replace. Using the non-greedy quantifier, will do the same thing, but a little bit slower because it needs, unnecessary, to look ahead after each repetition (theoretically).	[reply] [d/l]