Re^2: Checking if hash value exists without implicitly defining it

You don't even need the exists (assuming you don't have a weird freeform data structure):

if (Hash{$neededVal} and $Hash{$neededVal}{param1} and
    $Hash{$neededVal}{param1}{key1} > 4) {
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Re^3: Checking if hash value exists without implicitly defining it by Kenosis (Priest) on Feb 15, 2013 at 15:47 UTC
Yes, you're correct! Originally omitted `exists` when not testing for the final value--then overgeneralized. However, testing `$Hash{$neededVal}{param1}{key1}` would fail when `$Hash{$neededVal}{param1}{key1} == 0`, but expliciting testing the value, as you've shown, would remedy that.	[reply] [d/l] [select]