in reply to What this mean !$var ?
The !$varname construct is the ! operator followed by the variable $varname. The ! operator is logical negation--but I pronounce it mentally as "not". So your line of code, in my head, reads as: "if $results{$line} is 1 and not $dump_done then...".
...roboticus
When your only tool is a hammer, all problems look like your thumb.
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Re^2: What this mean !$var ?
by Hellena (Initiate) on Feb 19, 2013 at 15:35 UTC | |
by roboticus (Chancellor) on Feb 19, 2013 at 15:51 UTC |