Re^2: How can one generate all possible combinations with reference to string positions?

Hi kenneth,

Thanks for the script. It works nicely. I shall be glad if you kindly explain how to use and change the code 3-$l, 3-$h. Does it have any relationship with the number of L and H in the string following printf? Do the $h (1..2) and $l (1..2) refer to 2 levels each for H and L? Actually I tried to learn making some alterations in the script like 4-$l, 5-$h, $h(1..3), $l(1..4) etc.in appropriate places but I could not understand. This is because I donot know why the terms are used and how to change them. I hope you won't mind explain the terms. Please suggest me some reference texts for further study.

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Re^3: How can one generate all possible combinations with reference to string positions? by kennethk (Abbot) on Feb 25, 2013 at 15:37 UTC
The transform `3-$l` only works if you are working with 1 and 2 as your permuted set; it happens that for that set `3-$l` is equivalent to "the member of the set that is not `$l`". If you need any degree of flexibility, you should follow the code in Re: How can one generate all possible combinations with reference to string positions?, subject to BrowserUK's comments. #11929 First ask yourself `How would I do this without a computer?' Then have the computer do it the same way.	[reply] [d/l] [select]

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Re^3: How can one generate all possible combinations with reference to string positions?
by kennethk (Abbot) on Feb 25, 2013 at 15:37 UTC

The transform 3-$l only works if you are working with 1 and 2 as your permuted set; it happens that for that set 3-$l is equivalent to "the member of the set that is not $l". If you need any degree of flexibility, you should follow the code in Re: How can one generate all possible combinations with reference to string positions?, subject to BrowserUK's comments.

#11929 First ask yourself `How would I do this without a computer?' Then have the computer do it the same way.

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