------
/me wants to be the brightest bulb in the chandelier!

You can also "override"¹ a builtin with the &foo() syntax. You can also pass your current @_ through with it, if you leave off the parens.

sub time {
     print "Is on my side\n";
     print &bar, "\n";
}

sub bar {
     my ($baz) = @_;
     uc $baz;
}

&time('yes it is'); # prints 'Is on my side', a newline, followed by '
+YES IT IS'
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HTH

¹ OK, maybe it's not truly overriding, because of the special syntax you have to use to call it.

perl -e 'print "How sweet does a rose smell? "; chomp ($n = <STDIN>); 
+$rose = "smells sweet to degree $n"; *other_name = *rose; print "$oth
+er_name\n"'
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thanks

I forgot one

&foo;
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prototyping?

&foo;
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will call your subroutine with the @_ array set to the arguments of the caller.

an example

bar("a","b");

sub bar {
   foo();
   &foo();
   &foo;
}

sub foo {
($a, $b)=@_;
print "$a, $b\n";
}
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the call to bar will now print

,
,
a, b

Try doing a search on prototyping. Or, you could just click on prototyping, which will end up doing the same thing, eventually. :)

------
/me wants to be the brightest bulb in the chandelier!

Gee, this has been coming up a lot lately. I'll include my usual link to (tye)Re: A question of style. (:

# before declared - use ()
print_me();

# sub
sub print_me {
  print "hello there!\n";
}

# after declaration, you can drop the ()
# - but see prototyping as well...
print_me;
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cLive ;-)