pack construct in java

ghamrick has asked for the wisdom of the Perl Monks concerning the following question:

Hi Monks, my predecessor created an encryption routine in perl with the following construct as a key:

pack "a16",
    0x1d, 0x29, 0xda, 0xe8,
    0xa5, 0x98, 0x3c, 0x91,
    0x33, 0x1d, 0xae, 0x55,
    0x2f, 0xf6, 0x85, 0xec;
[download]

I need to use this same key in java to decrypt some of these items, and cannot figure out how to create this structure in java. I realize that this is not strictly a perl question, so please forgive if I have wandered off the path. Thank you.

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Re: pack construct in java by tobyink (Canon) on Mar 12, 2013 at 16:47 UTC
It's equivalent to the following string in Java `"29\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\ +u0000\u0000\u0000"` [download] For what it's worth, they probably meant one of: `pack "a"x16, ...; pack "c"x16, ...;` [download] ... which would have made more sense. In the version you posted, only the first hex number is used (0x1d == 29) and padded to 16 bytes; the rest are ignored. `package Cow { use Moo; has name => (is => 'lazy', default => sub { 'Mooington' }) } say Cow->new->name`	[reply] [d/l] [select]

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Re: pack construct in java
by tobyink (Canon) on Mar 12, 2013 at 16:47 UTC

It's equivalent to the following string in Java

"29\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\
+u0000\u0000\u0000"
[download]

For what it's worth, they probably meant one of:

pack "a"x16, ...;
pack "c"x16, ...;
[download]

... which would have made more sense. In the version you posted, only the first hex number is used (0x1d == 29) and padded to 16 bytes; the rest are ignored.

package Cow { use Moo; has name => (is => 'lazy', default => sub { 'Mooington' }) } say Cow->new->name

[reply]
[d/l]
[select]