in reply to about word boundary in RE

The whitespace between the words prevents the match. 

my $test = "asd asd";
    if ($test =~ /(.+\b)\s\1/)
    {
        print "Found $1 repeated\n";
    }

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Re^2: about word boundary in RE
by anaconda_wly (Scribe) on Apr 02, 2013 at 07:52 UTC
    Isn't there a word boundary before the whitespace? If (.+\b) already match, why I need the \s? I thought the output will be the first "asd" but not.
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