They help getting and setting the "pointer" of a filehandle.

PS: regarding your code

>   open ($hdl_sauv, "<",$file) || die "cannot open $file\n";

are you aware that $file is a filehandle and not a path?

EDIT:

If you wanna dup a filehandle you need something like "<&" as MODE. See open for details.

Though don't think this handles position the way you want to.

Have a look at seek. You cannot store the file handle as you desire but the position in the file using tell and later go back using seek.

UPDATE: A few seconds too late I was.

> UPDATE: A few seconds too late I was.

so what? =)

No reason to edit or strike your post!!!

Cheers Rolf

( addicted to the Perl Programming Language)

Thanks to you two! I think this will do it. Easy :)

ps : yes I am aware $file isn't file name, I just didn't know how to write what I wanted.

my $filename = $ARGV[0];
my $nb_lines = 0;
open (my $file, $filename) or die "Can't open '$filename': $!";
my $hdl_sauv;
while (<$file>) {
    $nb_lines++ ;
    if ($nb_lines == 5) {
    open ($hdl_sauv, "<",$file) || die "cannot open $file\n";
    }
}

my $saved_line = <$hdl_sauv>;
print "$saved_line\n";
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It looks like you want something like this:

my $filename = $ARGV[ 0 ] or die "Usage: $0 file\n";
open my $file, $filename or die "Can't open '$filename': $!";
while ( <$file> ) {
    last if $. == 5;
}

print;
[download]

I am trying to make a copy of the filehandle, that is *not* sharing file position.

Your code does not make a copy of the filehandle, nor does it share the file position.    It tries to open the previous filehandle as if it were a file name.    If you had opened $filename instead of $file you would have a different filehandle for the same file, but that still wold not solve your problem as it would be pointed at the beginning of the file.