Need A regex

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

I need a regex to match following number

Match                     No-Match
45123689745812            4514:4549 56378
451:896547899             4514|45698:1245|1245 
451:568:652:1236
4518:4569:5698:1256
[download]

The MAX numeric allowed is 20 and MIN is 12.I also saw a latest post which was something similar to this , But could not make much of it. Please guide...

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Re: Need A regex by CountZero (Bishop) on Apr 12, 2013 at 06:12 UTC
I think the most easy way to do this is to first delete from your string all '`:`' and then check if what remains fits `/\d{12,20}/` CountZero A program should be light and agile, its subroutines connected like a string of pearls. The spirit and intent of the program should be retained throughout. There should be neither too little or too much, neither needless loops nor useless variables, neither lack of structure nor overwhelming rigidity." - The Tao of Programming, 4.1 - Geoffrey James My blog: Imperial Deltronics	[reply] [d/l] [select]
Re: Need A regex by hdb (Monsignor) on Apr 12, 2013 at 06:24 UTC
If you refer to Regex Modification, it later turned out that the specification was far more complicated than stated in the initial question, see below. In order to make this more efficient, can you please confirm the exact requirements. `1. Number seq. with min 9 and max 15 digits. Like 145-1256-2365-789 2. First 3 and Last 3 should be numbers not diffrentiators. Like 123-1 +545645-123 3. Match can also be without a diffrentiator like 123456789147 4. The diffrentiator(same throughout sequence) can come any number of +times between the first and last 3 digits until the min and max lengt +h criteria is satisfied. Like 1213-456-789-1265` [download]	[reply] [d/l]
Re: Need A regex by AnomalousMonk (Archbishop) on Apr 12, 2013 at 10:12 UTC
See this recently posted reply to Regex Modification. It may be helpful. But in any event, CountZero's approach above seems both simple and effective. Update: This reply is a later and better version of the reply linked above.	[reply]