in reply to Re^2: Sorting by dependencies
in thread Sorting by dependencies
Well not A > B is equivalent to B >= A.
But the B == A part - i.e. B and A belong to the same phase - must be ignored, otherwise one risks that A comes after B in the unsorted output of a phase.
So translating to B > A should be safe, w/o loss of solutions.
Just modify the parser to translate different rules accordingly.
HTH! =)
Cheers Rolf
( addicted to the Perl Programming Language)
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