2 basic questions

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

Hello Monks,

I am pretty new to Perl. Kindly answer me if any of you can... :)

I have 2 questions today,

Question #1:

$check = "a";
$check++;
print $check;
exit;
[download]

This will give me answer as "b", but what should i do to get "d" or "e" (I mean to pass over 3 or 4 alphabets).

Question #2:

I have a string which have 2 alphabets, I need to trim it to 1 alphabet, ie, I only want the right alphabet, the left one should be trimmed out.

Example

 $input= "ab";
 $output = "b";
[download]

The alphabets can be any, not just "ab", it can be "cd" or "sp", In that case output should be "d" & "p" resp.

Thank you, Monks.

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Re: 2 basic questions by tobyink (Canon) on Apr 29, 2013 at 13:55 UTC
`use v5.12; my $check = "a"; $check++ for 1..3; # three letters say $check; $check++ for 1..24; # another 24 letters, but there's only 26 in the +alphabet, say $check; # so what happens now we've run off the end? # hmmm... that's handy. # it takes us to the next part of your question... my $input = $check; my $output = substr($input, 1, 1); # skip one character, take one char +acter say $output;` [download] `package Cow { use Moo; has name => (is => 'lazy', default => sub { 'Mooington' }) } say Cow->new->name`	[reply] [d/l]
Re^2: 2 basic questions by Anonymous Monk on Apr 29, 2013 at 14:50 UTC
Thx Toby	[reply]
Re: 2 basic questions by choroba (Cardinal) on Apr 29, 2013 at 14:00 UTC
The string increment is magical, but no other string operations are. Therefore, if you do not want to resort to ord arithmetics, you have to repeat the increment: `my $check = 'a'; $check++ for 1 .. 5;` [download] TIMTOWTDI. You can for example use substr: `my $check = 'cd'; substr $check, 0, 1, q();` [download] Or, use a substitution: `my $check = 'sp'; $check =~ s/^.//;` [download] لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ	[reply] [d/l] [select]
Re: 2 basic questions by toolic (Bishop) on Apr 29, 2013 at 13:56 UTC
For 1 you can use a for loop, for 2 you can use substr `use warnings; use strict; my $check = "a"; $check++ for 1..3; print $check; print "\n"; my $input= "ab"; print substr $input, -1, 1; print "\n"; __END__ d b` [download]	[reply] [d/l]
Re^2: 2 basic questions by Anonymous Monk on Apr 29, 2013 at 14:54 UTC
thx Monk...	[reply]
Re: 2 basic questions by ww (Archbishop) on Apr 29, 2013 at 14:14 UTC
Very basic and better answered for yourself by reading `perldoc perlintro` (from your command line)... and -- as is often the case -- correctly answered in many different ways. Here is a (partial) answer for each question: `my $check = "A"; for (1..2) { $check++; } say $check; #2: my $input = "xy"; $input = reverse ($input); chop $input; say $input;` [download] The first, obviously, is a simplied loop using the range operator (alternate syntax is shown by other replies above); the second takes advantage of the otherwise little-used `chop`. Note that it will "work" even if your charpair is NOT an ordered pair. Please take these for examples, and set yourself the task of finding at least two other ways to answer each of your questions. If you didn't program your executable by toggling in binary, it wasn't really programming!	[reply] [d/l] [select]
Re^2: 2 basic questions by Anonymous Monk on Apr 29, 2013 at 14:53 UTC
Thank you...	[reply]
Re: 2 basic questions by karlgoethebier (Abbot) on Apr 29, 2013 at 14:35 UTC
Another TIMTOWTDI: `my $result = (split "", "ab")[(length(qq(ab))-1)]; print $result;` [download] Please note: with subtraction ;-) Update: Two more... `$result = pop @{ [ split( "", "ab" ) ] }; print qq($result\n); $result = splice( @{ [ split( "", "ab" ) ] }, -1 ); print qq($result\n);` [download] Perhaps this is the reason why some folks hate perl? Regards, Karl P.S.: length splice pop «The Crux of the Biscuit is the Apostrophe»	[reply] [d/l] [select]
Re: 2 basic questions (perlintro) by Anonymous Monk on Apr 29, 2013 at 13:56 UTC
read perlintro and you'll know the answer, don't rely on magic increment or chr and ord, use "substitution" or transliteration operator	[reply]
Re: 2 basic questions by Random_Walk (Prior) on Apr 29, 2013 at 14:58 UTC
Just playing, may not work in your character set: `perl -le "while(1){$a=$a?$a:ord'a';print chr$a;$a=++$a%ord'{';sleep 1} +"` [download] This probably will though `perl -le "$_='x';while(1){s/aa/a/;print$_++;sleep 1}"` [download] Cheers, R. Pereant, qui ante nos nostra dixerunt!	[reply] [d/l] [select]