Re^2: scoping inside the loop

in reply to Re: scoping inside the loop
in thread scoping inside the loop

Thanks LanX.Understood but in second case which is a working condition $i's scope is in outer loop but how it got tucked in to inside loop.My understanding is if my is before a variable it's existence is strictly with in that boundary. In case 2 my is associated with $i so i think it only resides outside or where it is defined but i am confused how it got transported to loop.

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Re^3: scoping inside the loop by LanX (Saint) on May 17, 2013 at 18:40 UTC
No, up to the point that you declare an inner $i with `my` the outer one is used. No inner `my $i` means the outer one is everywhere available. These are universal rules for lexical variables in almost any language! Have a look at the scoping-article I linked. Cheers Rolf ( addicted to the Perl Programming Language)	[reply] [d/l] [select]

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