stuffing an array inside a list

vyeddula has asked for the wisdom of the Perl Monks concerning the following question:

Case1:No issue

my @array1=(1,2,3);
my @array2;
@array2=(@array1,4,5,6);
print"@array2\n";
[download]

This printed 1 2 3 4 5 6 which is expected

Case2:I tried to extend this to qw and reason for my question

my @array1=qw(Jan Feb Mar);
my @array2;
@array2=qw(@array1 Jan Feb Mar);
print"@array2\n";
[download]

This printed @array1 Jan Feb Mar

Am i missing any basic thing here. How to stuff array1 contents inside array2 when qw is used?Thanks

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Re: stuffing an array inside a list by Grimy (Pilgrim) on May 26, 2013 at 01:34 UTC
`qw` doesn't perform any interpolation: anything inside a `qw` is interpreted as litteral characters (with two minor exceptions: \\ and \delimiter). That's why you got this output: inside a `qw`, `@array1` is no more special than `Jan`. Try this: `@array2 = (@array1, qw(Jan Feb Mar));` [download] Alternatively, you could use `push`, like so: `my @array2 = @array1; push @array2, qw(Jan Feb Mar);` [download]	[reply] [d/l] [select]
Re: stuffing an array inside a list by NetWallah (Canon) on May 26, 2013 at 01:37 UTC
"@" does not interpolate inside ~~"Quote like operators"~~ (qw). Update - corrected to allow for qq, per Grimy(++) below. "I'm fairly sure if they took porn off the Internet, there'd only be one website left, and it'd be called 'Bring Back the Porn!'" -- Dr. Cox, Scrubs	[reply]
Re^2: stuffing an array inside a list by Grimy (Pilgrim) on May 26, 2013 at 01:42 UTC
While it is true that `@` doesn't interpolate inside `qw`, it does interpolate inside `qq`, which is also a “Quote-like operator”.	[reply] [d/l] [select]