Re^4: Why doesn't perl optimize this?

You seem to believe in magical powers of static code analysis in a dynamic language.

plz tell me

 
sub func {
  my ($code,@a) = @_;
  my $b = [@a];
  eval $code;
  return $b;
}
[download]

How is the compiler supposed to know that '@a' can be destroyed w/o knowing what happens in '$code' at runtime?

Cheers Rolf

( addicted to the Perl Programming Language)

Comment on Re^4: Why doesn't perl optimize this? Download Code

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Re^5: Why doesn't perl optimize this? by nbtrap (Sexton) on Jun 05, 2013 at 01:57 UTC
I agree that the compiler can't know in the case you cite. But what about the case I cited?	[reply]
Re^6: Why doesn't perl optimize this? by LanX (Saint) on Jun 05, 2013 at 02:12 UTC
> But what about the case I cited? It's extremely complicated and risky to cover ALL edge cases. It's not worth it and BrowserUK already told you! If you think such code analysis is easy, please better try implementing a JIT compiler for Perl... Cheers Rolf ( addicted to the Perl Programming Language)	[reply]