Re: Using Splice with Two Arrays within a loop

I don't quite understand why you need a different approach to the same goal in your second snippet. I do think it's clever to have passed a count value for the first array as a way of dealing with the fact that Perl flattens lists, but references are built into the language, in part, to deal with that problem more conveniently. Passing a count is so... "C". ;)

However, if I were doing it, I would just use List::MoreUtils "zip" function (also known as mesh):

use List::MoreUtils qw( zip );

my @first  = qw( can unlock secret );
my @second = qw( you the    code?  );

my @mixed = zip @first, @second;

print "@mixed\n";
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Dave

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Re^2: Using Splice with Two Arrays within a loop by Anonymous Monk on Jun 10, 2013 at 17:34 UTC
Hi, Sorry to clarify I have an assignment that requires the following to be done: "This program can be made both shorter and faster by using a built-in function named splice that will remove a specified number of elements from the @_ array at once, rather than the one-at-a-time that shift does." As you can see from my output I am doing something wrong. Can someone help me out. I need to use splice to resolve this. Thanks	[reply]

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Re^2: Using Splice with Two Arrays within a loop
by Anonymous Monk on Jun 10, 2013 at 17:34 UTC

Sorry to clarify I have an assignment that requires the following to be done: "This program can be made both shorter and faster by using a built-in function named splice that will remove a specified number of elements from the @_ array at once, rather than the one-at-a-time that shift does." As you can see from my output I am doing something wrong. Can someone help me out. I need to use splice to resolve this.

[reply]