in reply to special character substitution

Works for me: 
$_ = "T}\@T...T}\@T{";
s/T\}\@T.*T\}\@T\{/\\(bu/sm;
print;

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Output: 

\(bu

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لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ

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Re^2: special character substitution
by bill b (Initiate) on Jun 10, 2013 at 20:16 UTC
    Thanks. I'm an idiot--I was inadvertently erasing the \ in another part of postprocessing. Sigh. thanks again, bill
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