Re^4: Thoughts on replacing -> with .

It is like += and .=, which modify the left-hand side by the right hand side.

$a += $b adds the right hand side ($b) to the left hand side, $a, and assigns the result to $a.

$a .= $b appends $b to $a and assigns the result to $a.

$a ~= $b xor's $b and $a and assigns the result to $a.

As this is a relatively uncommon use, it maybe makes this interchange currently even harder to spot than later the use of =~ and ~=.

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Re^5: Thoughts on replacing -> with . by Ralesk (Pilgrim) on Jun 12, 2013 at 11:38 UTC
But XOR-assign is supposed to be `$a ^= $b`...	[reply] [d/l]
Re^5: Thoughts on replacing -> with . by choroba (Cardinal) on Jun 12, 2013 at 11:38 UTC
I am getting a syntax error for `$a ~= $b` [download] لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ	[reply] [d/l]
Re^6: Thoughts on replacing -> with . by Corion (Patriarch) on Jun 12, 2013 at 11:47 UTC
Err - yes. I wonder how I came to this interpretation and I'm sorry I did not test it before...	[reply]
Re^6: Thoughts on replacing -> with . by Grimy (Pilgrim) on Jun 13, 2013 at 18:21 UTC
Correct. On the other hand, `:$ ~= $b` does work, but is has nothing to do with XOR.	[reply] [d/l]