opening a file

torres09 has asked for the wisdom of the Perl Monks concerning the following question:

Hey

i have opened a file as shown in code and called sub routines which need to access the file , but i can't open the file . I am new to perl so any form of help is appreciated

print " Please input your new csv file \n";
my $ csv_name =<>;
 my $file_csv="$csv_name";     
    open(FILE_csv,"<","$file_csv")|| die ("can't open the csv file \n"
+);          

@array_A= column_segregation_Spec_values (1);  # function call

close FILE;
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Re: opening a file by choroba (Cardinal) on Jun 13, 2013 at 14:19 UTC
There are several issues: After reading from the standard input, the line ends in a newline. This newline is not a part of the filename, so remove it. See chomp. Why do you declare the variable $file_csv? Its value is identical to $csv_name (the space after the `$` sigil is tolerated by Perl, but I would recommend removing it). You are closing the `FILE` filehandle, but opening the `FILE_csv` one. If you turned warnings on, Perl would tell you. Update: It is easier to send lexical filehandles as parameters to subroutines. Do not use bareword filehandles. لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ	[reply] [d/l] [select]

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Re: opening a file
by choroba (Cardinal) on Jun 13, 2013 at 14:19 UTC

After reading from the standard input, the line ends in a newline. This newline is not a part of the filename, so remove it. See chomp.
Why do you declare the variable $file_csv? Its value is identical to $csv_name (the space after the $ sigil is tolerated by Perl, but I would recommend removing it).
You are closing the FILE filehandle, but opening the FILE_csv one. If you turned warnings on, Perl would tell you.
Update: It is easier to send lexical filehandles as parameters to subroutines. Do not use bareword filehandles.

لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ

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