Re: perlsub prototype sub(_) sub foo(

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Re^2: perlsub prototype sub(_) sub foo(_) by farang (Chaplain) on Jun 30, 2013 at 13:30 UTC
If you are referring to my node, there's probably nothing wrong with the documentation, just my quick reading of it. When it says `you can use _ in place of $` I got the idea that prototypes `(_)` and `($)` would be the same, which is not the case. `sub foo(_){ warn @_ } sub goo($){ warn @_ } foo(); goo();` [download] output: `Not enough arguments for main::goo at pm3 line 4, near "()"` `Execution of pm3 aborted due to compilation errors.`	[reply] [d/l]
Re^2: perlsub prototype sub(_) sub foo(_) by Anonymous Monk on Jun 30, 2013 at 14:00 UTC
Whats wrong with the documentation? It didn't show up in the search :) It doesn't mention `(_)` and `(_)` is not on the list `Declared as Called as`	[reply] [d/l] [select]
Re^3: perlsub prototype sub(_) sub foo(_) by LanX (Saint) on Jun 30, 2013 at 16:27 UTC
TIP: a file-search in perlsub#Prototypes for `_` (surrounded by spaces) helps! =) Cheers Rolf ( addicted to the Perl Programming Language)	[reply] [d/l]
Re^4: perlsub prototype sub(_) sub foo(_) by Anonymous Monk on Jun 30, 2013 at 18:34 UTC
Yup, and now sub (_) also works	[reply]